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70x-25x^2=40
We move all terms to the left:
70x-25x^2-(40)=0
a = -25; b = 70; c = -40;
Δ = b2-4ac
Δ = 702-4·(-25)·(-40)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-30}{2*-25}=\frac{-100}{-50} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+30}{2*-25}=\frac{-40}{-50} =4/5 $
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